2x^2+13x=132

Solution for 2x^2+13x=132 equation:

2x^2+13x=132

We move all terms to the left:

2x^2+13x-(132)=0

a = 2; b = 13; c = -132;
Δ = b2-4ac
Δ = 132-4·2·(-132)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-35}{2*2}=\frac{-48}{4}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+35}{2*2}=\frac{22}{4}
=5+1/2
$